Question

Найти y'
Y=3x^2 x^3
Y=2/x^2
Y=1/3x^5
Y=x^5/175

Answer 1

y'=(3x^2x^3)'=3*2x*3x^2=18x^3
y' =(2/x^2)'=(2x^(-2))'=2*(-2)*x^(-3)=-4/x^3
y'=1/3x^5=5/3x^4
y'=(x^5)/175=(5/175)*x^4=(x^4)/35