Question

решите задания по алгебре

Answer 1

1)
$3 times sqrt[4]{16} - 4 times sqrt[3]{27} = 3 times 2 - 4 times 3 = 6 - 12 = 6$
2)
$14 - sqrt[4]{196} times {14}^{ frac{1}{2} } = 14 - sqrt[4]{ {14}^{2} } times sqrt{14} = 14 - sqrt{14} times sqrt{14} = 14 - 14 = 0$
3)
$6 times {49}^{ frac{1}{2} } - {64}^{ frac{1}{3} } = 6 times sqrt{49} - sqrt[3]{64} = 6 times 7 - 4 = 38$
4)

$sqrt{10 - sqrt{96} } times sqrt{10 + sqrt{96} } = sqrt{ {10}^{2} - { sqrt{96} }^{2} } = sqrt{100 - 96} = sqrt{4} = 2$
5)
$4 times sqrt[3]{25} times 2 times sqrt[3]{40} = 8 times sqrt[3]{25 times 40} = 8 times sqrt[3]{1000} = 8 times 10 = 80$
6)
$4 times sqrt[3 ]{ frac{540}{20} } = 4 times sqrt[3]{27} = 4 times 3 = 12$