Question

привести к рациональному виду числитель дроби

Answer 1

$frac{sqrt{2}}{2}times1=frac{sqrt{2}}{2}timesfrac{sqrt{2}}{sqrt{2}}=frac{sqrt{2}timessqrt{2}}{2timessqrt{2}}=frac{2}{2sqrt{2}}=frac{1}{sqrt{2}}$

$frac{sqrt{6}}{3}times1=frac{sqrt{6}}{3}timesfrac{sqrt{6}}{sqrt{6}}=frac{sqrt{6}timessqrt{6}}{3timessqrt{6}}=frac{6}{3sqrt{6}}=frac{2}{sqrt{6}}$

$frac{sqrt{5}}{5}times1=frac{sqrt{5}}{5}timesfrac{sqrt{5}}{sqrt{5}}=frac{sqrt{5}timessqrt{5}}{5timessqrt{5}}=frac{5}{5sqrt{5}}=frac{1}{sqrt{5}}$

$frac{sqrt{10}}{5}times1=frac{sqrt{10}}{5}timesfrac{sqrt{10}}{sqrt{10}}=frac{sqrt{10}timessqrt{10}}{5timessqrt{10}}=frac{10}{5sqrt{10}}=frac{2}{sqrt{10}}$