Question

Найдите производную
f(x)=(3- (4/x^4))(x^2+1)

Answer 1

$f(x)=(3-frac{4}{x^4} )(x^2+1)\ \ f'(x)=(3-frac{4}{x^4} )'(x^2+1)+(3-frac{4}{x^4} )(x^2+1)'=\ \ frac{16}{x^5} (x^2+1)+2x(3-frac{4}{x^4} )=\ \ frac{16}{x^3} +frac{16}{x^5} +6x-frac{8}{x^3} =frac{16}{x^5} +frac{8}{x^3} +6x$