Question

$frac{x(x + 6)}{2} - frac{x(x + 14)}{3} - frac{ {x}^{2} + 1 }{6} = 0$
помогите решить задачу

Answer 1

$frac{x(x + 6)}{2} - frac{x(x + 14)}{3} - frac{ {x}^{2} + 1 }{6} = 0 \ 3 {x}^{2} + 18x - 2 {x}^{2} - 28x - {x}^{2} - 1 = 0 \ - 10x = 1 \ x = - frac{1}{10} = - 0.1$