Question

для функций f(x)=x^3+2x^2-1
Найти f(0) , f(1)

Answer 1

$f(0) = {0}^{3} + 2 times {0}^{2} - 1 = - 1 \ f(1) = {1}^{3} + 2 times {1}^{2} - 1 = 1 + 2 - 1 = 2$