Question

Log3(1-6x)=log3(17-x2)

Answer 1

$log_{3}(1 - 6x) = log_{3}(17 - {x}^{2} ) \ 1 - 6x = 17 - {x}^{2} \ {x }^{2} - 6x - 16 = 0 \ (x - 8)(x + 2) = 0 \ x1 = 8 \ x2 = - 2$
ОДЗ
$\ left { {{1 - 6x > 0} atop {17 - x ^{2} > 0}} right.$
ОДЗ удовлетворяет лишь
$x = - 2$
Ответ
$x = - 2$