Question

Пожалуйста Помогите решить
а)4х+7=3(х-1)
Б)3(x-1)+4(x+1)=6(x+2)
Г)3(х-1,1)+4(1,2х+2)=7,3х+0,7

Answer 1

$4x + 7 = 3(x - 1) \ 4x + 7 = 3x - 3 \ 4x - 3x = - 10 \ x = - 10$

$3(x - 1) + 4(x + 1) = 6(x + 2) \ 3x - 3 + 4x + 4 = 6x + 12 \ x = 11$

$3(x - 1.1) + 4(1.2x + 2) = 7.3x + 0.7 \ 3x - 3.3 + 4.8x + 8 = 7.3x + 0.7 \ 0.5x = - 4 \ x= - 8$