Question

Центр, R=?

$x {}^{2} + y {}^{2} + z {}^{2} - x + 2y - 3z - 4 = 6$

Answer 1

$( {x - frac{1}{2} })^{2} + ( {y + 1})^{2} + ( {z - frac{3}{2} })^{2} = frac{1}{4} + 1 + frac{9}{4} + 4 + 6 \ ( {x - frac{1}{2} })^{2} + ( {y + 1})^{2} + ( {z - frac{3}{2} })^{2} = frac{27}{2} \ ( {x - frac{1}{2} })^{2} + ( {y + 1})^{2} + ( {z - frac{3}{2} })^{2} = ({ frac{3 sqrt{3} }{ sqrt{2} } })^{2}$
Ответ: { frac{3 sqrt{3} }{ sqrt{2} } }