Question

Решите систему {у=х²
{ х=у²

Answer 1

$left { {{y=x^2} atop {x=y^2}} right. \ \ x=y^2=(x^2)^2=x^{4}\ \ x^{4}-x=0\ \x(x^3-1)=0 \ \ x(x-1)([tex]x_{1} =0;y_{1} =0\ \ x_{2} =1;y_{2} =1\ \ x^2+x+1neq 0,t.k.D<0\ \ otvet:(0;0)(1;1)$)=0\ \[/tex]