Question

$frac{log_2{20} }{log_2{12} }+ log_12{0,05}$

Answer 1

$frac{ log_{2}(20) }{ log_{2}(12) } + log_{12}(0.05) = log_{12}(20) + log_{12}(0.05) = \ = log_{12}(20 times 0.05) = log_{12}(1) = 0$


ОТВЕТ: 0