Question

Найдите нули функции у=3х^2-12х+2

Answer 1

$y = 3 {x}^{2} - 12x + 2 \ 3 {x}^{2} - 12x + 2 = 0 \ d = {b}^{2} - 4ac = {12}^{2} - 4 times 3 times 2 = 144 - 24 = 120 \ x1= frac{12 +2 sqrt{30} }{6} = 2 + frac{1}{3} sqrt{30} \ x2 = frac{12 - 2 sqrt{30} }{6} = 2 - frac{1}{3} sqrt{30}$