Question

$8x^{2}*(2x^{2} -1)+(x^{2} +1)*(x^{2} -1)=ax^{4}+ bx^{2}+c$

Найдите значение a, b, c

Answer 1

$16x^{4} -8x^{2} +(x^{4} -1)=ax^{4}+b x^{2}+c\16x^{4} -8x^{2} +x^{4} -1=ax^{4}+b x^{2}+c\16x^{4} -7x^{2} -1=ax^{4}+b x^{2}+c\\a=16; b=-7; c=-1$