Question

Найдите лимит. Не используя правило Лопиталя. Даю максимум баллов.

Answer 1

I hope this helps you

Answer 2

I love you

Answer 3

pliz help me, two questions

Answer 4

$lim(x -> frac{pi}{6}) frac{ { cos}^{2}(3x) }{1 - sin(3x) } = | frac{0}{0} | = | { cos }^{2} (3x) = 1 - { sin}^{2} (3x) = (1 - sin(3x) )(1 + sin(3x) )| = lim(x -> frac{pi}{6}) frac{(1 - sin(3x) )(1 + sin(3x))}{1 - sin(3x)} = lim(x -> frac{pi}{6})(1 + sin(3x)) = 1 + 1 = 2$