Question

2cosx^2=1-sinx решите пж

Answer 1

$2(1 - { sin }^{2} x) = 1 - sin(x) \ 2 { sin}^{2} x - sin(x) - 1 = 0 \ sin(x) = 1 \ x = pi div 2 + 2pi times k \ \ sin(x) = - frac{1}{2} \ x = {( - 1)}^{n+1} pi div 6 + pi times n$