Question

Решите систему уравнений методом подстановки:
( х^2+ху-х-у=2
(х-у=2

Answer 1

$left { {{x^{2}+xy-x-y=2}atop {x-y=2}} right.\left { {{y=x-2} atop {x^{2}+x(x-2)-x-(x-2)=2} } right. \left { {{y=x-2} atop {x^{2}+x^{2}-2x-x-x+2=2}} right.\left { {{y=x-2} atop {2x^{2}-4x=0} } right.\left { {{y=x-2} atop {x^{2}-2x=0} } right.\left { {{y=x-2} atop {x(x-2)=0}} right.\left { {{y=x-2} atop {x=2;x=0}} right.\1)left { {x_{1}= 2}} atop {y_{1}=0} } right. \2)left { {{x_{2}=0} atop {y_{2}=-2} } right.$

Ответ: (2 ; 0) , ( 0 ; - 2)