Question

Решите плз
a)$frac{3(x-2y)}{4(2y-x)}$
$frac{3b(5a-6)}{6-5a}$
$frac{x^{2}-16y^{2}} {4y+x}$

Answer 1

$frac{3(x-2y)}{4(2y-x)}=frac{-3(2y-x)}{4(2y-x)}=-frac{3}{4}$

$frac{3b(5a-6)}{6-5a}=frac{-3b(6-5a)}{6-5a}=-3b$

$frac{x^{2}-16y^{2}}{4y+x}=frac{(x-4y)(x+4y)}{x+4y}=x-4y$

Answer 2

$frac{3(x-2y)}{4(2y-6)} =frac{3(x-2y)}{4*(-(x-2y))} =frac{3*(-1)}{4} =frac{-3}{4} =-frac{3}{4} \\frac{3b(5a-6)}{6-5a} =frac{3b(5a-6)}{-(5a-6)} =3b*(-1)=-3b\\frac{x^2-16y^2}{4y+x} =frac{(x-4y)(x+4y)}{4y+x} =x-4y$