Question

Помогите!

1) cos(pi/2-x)=1
2) sin(pi-x)=-1

Answer 1

$1) cos(frac{pi}2 - x) = 1\sinx = 1\x = frac{pi}2 + 2pi k\2) sin(pi - x) = -1\sinx = -1\x = -frac{pi}2 + 2pi k$