Question

Решите производную.....

Answer 1

$g(t)=(t+4), sqrt[3]{t}\\g'(t)=sqrt[3]{t}+(t+4)cdot frac{1}{3}cdot t^{-2/3}=sqrt[3]{t}+frac{t+4}{3cdot sqrt[3]{t^2}}\\\f(u)=(2u-sqrt{u})^2\\f'(u)=2cdot (2u-sqrt{u})cdot (2-frac{1}{2sqrt{u}})$