Question

Выполните умножение:
$- frac{1}{9}(0.5 {a}^{2} {b}^{2} - ab + 0.9)( - ab) = ... \ - {b}^{3} ( - 0.3 {a}^{2} b : - 0.4ab + 1) times frac{1}{6} {a}^{2} {b}^{2} = ...$

Answer 1

1)
$- frac{1}{9} ( frac{5}{10} a {}^{2} b {}^{2} - ab + frac{9}{10} )( - ab) = \ \ =( - frac{1}{18} a {}^{2} b {}^{2} + frac{1}{9} ab - 0.1)( - ab) = \ \ = frac{1}{18} a {}^{3} b {}^{3} - frac{1}{9} a {}^{2} b {}^{2} + 0.1ab$

2)
$- b {}^{3} ( - 0.3a {}^{2} b - 0.4ab + 1) times frac{1}{6} a {}^{2} b {}^{2} = \ \ = ( frac{3}{10} a {}^{2} b {}^{4} + frac{4}{10} ab {}^{4} - b {}^{3} ) times frac{1}{6} a {}^{2} b {}^{2} = \ \ = 0.05a {}^{4} b {}^{6} + frac{1}{15} a {}^{3} b {}^{6} - frac{1}{6} a {}^{2} b {}^{5}$