Question

2sinx-cosx/2cosx+sinx=3 найти tgx

Answer 1

$frac{2, sinx-cosx}{2, cosx-sinx}=Big [, frac{:cosx}{:cosx}, Big ]=frac{2, tgx-1}{2-tgx}=3; ; Rightarrow \\2, tgx-1=3(2-tgx)\\2, tgx-1=6-3tgx\\5, tgx=5\\tgx=1qquad (cosxne 0)$