Question

ПО ДЕЙСТВИЯМ!!Непроходит мимо добрые люди

Answer 1

!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answer 2

$(frac{(a+3)(a+3)}{(a-3)(a+3)} -frac{(a-3)(a-3)}{(a-3)(a+3)}) *frac{9-a^2}{3a^2+27} =\\frac{(a+3)(a+3)-(a-3)(a-3)}{(a-3)(a+3)} *frac{9-a^2}{3a^2+27}=\\frac{a^2+6a+9-(a^2-6a+9)}{a^2-9} *frac{-1(a^2-9)}{3(a^2+9)} =\\-frac{a^2+6a+9-a^2+6a-9)}{a^2-9} *frac{a^2-9}{3(a^2+9)} =\\-frac{12a}{3(a^2+9)} =\\-frac{4a}{a^2+9}$

$(frac{8m}{m+7}- frac{15m}{m^2+14m+49}): frac{8m+41}{m^2-49}+ frac{7m-49}{m+7} =(frac{8m}{m+7}- frac{15m}{(m+7)^2})* frac{(m-7)(m+7)}{8m+41}+ frac{7m-49}{m+7} =(frac{8m(m+7)}{(m+7)(m+7)}- frac{15m}{(m+7)^2})* frac{(m-7)(m+7)}{8m+41}+ frac{7m-49}{m+7} =frac{8m^2+56m-15m}{(m+7)(m+7)} * frac{(m-7)(m+7)}{8m+41}+ frac{7m-49}{m+7} =frac{m(8m+41)(m-7)}{(m+7)(8m+41)} +frac{7m-49}{m+7} =frac{m(m-7)}{m+7} +frac{7(m-7)}{m+7}=frac{m(m-7)+7(m-7)}{m+7} =frac{(m+7)(m-7)}{m+7} =m-7$