Question

(2a-1)/(10a^2-a-2)

б) (6a^2-5a+1)/1-4a^2) 

Answer 1

1)(2а-1)/10(а-0,5)(а+0,4)

(2а-1)/5(2а-1)(а+0,4)

Ответ:1/(5а+2)

 

2)6(а-0,5)(а-1/3)/(1+2а)*-(2а-1)

   (2а-1)(3а-1)/(1+2а)*-(2а-1)

  Ответ: (3а-1)/(-1-2а)

Answer 2

a) $frac{2a-1}{10a^{2}-a-2}=frac{2a-1}{10(a-frac{1}{2})(a+frac{2}{5})}=frac{2a-1}{5(2a-1)(a+frac{2}{5})}=frac{1}{5(a+frac{2}{5})}=frac{1}{5a+2}$

б)$frac{6a^{2}-5a+1}{1-4a^{2}}=frac{6(a-frac{1}{2})(a-frac{1}{3})}{(1-2a)(1+2a)}=frac{3(2a-1)(a-frac{1}{3})}{-(2a-1)(2a+1)}=frac{3(a-frac{1}{3})}{-(2a+1)}=frac{3a-1}{-(2a+1)}$

$frac{-(1-3a)}{-(2a+1)}=frac{1-3a}{2a+1}$