Question

Решите плез
8^(x-1)+8^(x-2)*6+33*7^(x-2)-7^x=0

Answer 1

$displaystyle 8^{x-1}+8^{x-2}*6+33*7^{x-2}-7^x=0;\frac{8^x}{8}+frac{6*8^x}{64}=7^x-frac{33*7^x}{49};\frac{(4+3)*8^x}{32}=frac{(49-33)7^x}{49};\frac{7*8^x}{32}=frac{16*7^x}{49};\7^38^x=8^37^x; :7^37^x;\(frac{8}{7})^x=(frac{8}{7})^3;\boxed{x=3;}$