Question

Помогите пожалуйста!! 13целых3/8-11целых19/12

Answer 1

Решить пример.

# 1 способ

$13dfrac{3}{8} - 11dfrac{19}{12} = dfrac{13*8 + 3}{8} - dfrac{11*12 + 19}{12} = dfrac{107}{8} - dfrac{151}{12} =\= dfrac{107*3 - 151 * 2}{24} = dfrac{321 - 302}{24} = dfrac{19}{24}.$

# 2 способ

$13dfrac{3}{8} - 11dfrac{19}{12} = 13dfrac{3}{8} - 12dfrac{7}{12} = (13 - 12) + left(dfrac{3}{8} - dfrac{7}{12}right) =\= 1 + dfrac{3*3 - 7*2}{24} = 1 - dfrac{5}{24} = dfrac{24 - 5}{24} = dfrac{19}{24}.$

Ответ: $dfrac{19}{24}.$