Question

решите плиииииииз сложнааа

Answer 1

$sqrt{2x + 3} = x \ 2x + 3 = {x}^{2} \ {x}^{2} - 2x - 3 = 0 \ x1 = 3 \ x2 = - 1$
$sqrt{2x + 1} = x - 1 \ 2x + 1 = {x}^{2} - 2x + 1 \ {x}^{2} - 4x =0 \ x(x - 4) = 0 \ x1 = 0 \ x2 = 4$

Answer 2

спасибо большое