Question

1)Log2 20/log2 12+log12 0.005
2)log6 4/log6 2
3log9 2/log81 2
Помогите решить срочно

Answer 1

$log_{2} 20/log_{2} 12+log_{12} 0,005=log_{12} 20+log_{12} 0,005=log_{12}(20*0,005) = log_{12} 0,1=-0.93$

$log_{6} 4/log_{6} 2=log_{2} 4=2$

$log_{9} 2/log_{81} 2 = log_{9} 2/log_{9^{2} } 2 = log_{9} 2/{[log_{9} 2]/2}=2$