Question

2√20 √250
⁻⁻⁻⁻⁻ + ⁻⁻⁻⁻⁻
√32 2
помогите 30 б

Answer 1

$displaystylett frac{2sqrt{20}}{sqrt{32}}+frac{sqrt{250}}{2}=frac{4sqrt{5}}{4sqrt{2}}+frac{5sqrt{10}}{2}=frac{sqrt{5}}{sqrt{2}}+frac{5sqrt{10}}{2}=frac{sqrt{5}cdotsqrt{2}}{sqrt{2}cdotsqrt{2}}+frac{5sqrt{10}}{2}=\\\=frac{sqrt{10}}{2}+frac{5sqrt{10}}{2}=frac{6sqrt{10}}{2}=3sqrt{10}$