Question

(40/28)в 7-ой степени•(7/8)в сю7-ой степени•(2/5)в 7-ой степени =?

Answer 1

$( frac{40}{28} ) {}^{7} times ( frac{7}{8} ) {}^{7} times (frac{2}{5} ) {}^{7 } = ( frac{40 times 7 times 2}{28 times 8 times 5} ) {}^{7}$
$( frac{1}{2} ) {}^{7} = frac{1}{128}$