Question

решите квадратные уравнения

Answer 1

$1) - 2 {x}^{2} + 5x + 3 = 0 \ d = {5}^{2} - 4 times ( - 2) times 3 = 25 + 24 = 49 \ x1 = frac{ - 5 + 7}{ - 4} = - 0.5 \ x2 = frac{ - 5 - 7}{ - 4} = 3$
$2) {x}^{2} - 5x + 3 = 0 \ d = 25 - 4 times 1 times 3 = 13 \ x1 = frac{5 + sqrt{13} }{2} \ x2 = frac{5 - sqrt{13} }{2}$