Question

x3(куб)+3x2(квадрат)-4x-12=0

Answer 1

х^3 + 3x^2 - 4x - 12 = 0

x^2(x+3) - 4(x+3) = 0

(x+3)(x^2 - 4) = 0

(x+3)(x-2)(x+2) = 0

x=-3

x=2

x=-2