Question

cos2xsin2x = - √3/4
помогите решить

Answer 1

$Cos2xSin2x=-frac{sqrt{3}} {4}\\2Cos2xSin2x=-frac{sqrt{3}} {4}*2\\Sin4x=- frac{sqrt{3}} {2}\\4x=(-1) ^{n}arcSin(- frac{sqrt{3}} {2})+ pi n\\4x=(-1)^{n+1} frac{pi} {3} +pi n\\x=(-1)^{n+1} frac{pi} {12}+ frac{pi n} {4}$

Везде добавить n ∈ z