Question

Помогите пожалуйста!
9x^2+6x+1=0

Answer 1

9x^2+6x+1=0
(3x+1)^2=0 <=> 3x+1=0
x=-1/3

Answer 2

$9x {}^{2} + 6x + 1 = 0 \ \ x1.2 = frac{ - 6 + - sqrt{6 {}^{2} - 4 times 9 times 1 } }{2 times 9} = frac{ - 6 + - sqrt{36 - 36} }{18} = frac{ - 6 + - sqrt{0} }{18} = frac{ - 6 + - 0}{18} \ \ x1 = frac{ - 6 + 0}{18} = frac{ - 6}{18} = - frac{1}{3} \ \ x2 = frac{ - 6 - 0}{18} = frac{ - 6}{18} = - frac{1}{3}$

Ответ: $- frac{1}{3}$