Question

корень2x-1=3
решить уравнение

Answer 1

$sqrt{2x-1} =3$

$2x-1 ge 0$

$2x ge 1 /:2$

$x ge frac{1}{2}$

$x in leftlangle frac{1}{2};+ infty right)$

$sqrt{2x-1} =3 /()^2$

$2x-1=9$

$2x=9+1$

$2x=10 /:2$

$x=5$