Question

y=3x4-5tgx-3x
y=x2 cos x
найти производную

Answer 1

$y=3x^{4} -5tgx-3x\y'=(3x^{4})' -(5tgx)'-(3x)'\y'=12x^{3} -frac{5}{cos^{2}x  }-3$

$y=x^{2} cosx\y'=(x^{2})' cosx+x^{2} (cosx)'\y'=2x* cosx-x^{2}sinx$