Question

решить неравенство (2/7)^x^2 больше (3.5)^x-2

Answer 1

${( frac{2}{7} )}^{ {x}^{2} } > ({ frac{35}{10} )}^{x - 2} \ {( frac{2}{7} )}^{ {x}^{2} } > ({ frac{7}{2} )}^{x - 2} \ {( frac{2}{7} )}^{ {x}^{2} } > ({ frac{2}{7} )}^{2 - x} \ {x}^{2} < 2 - x \ x {}^{2} + x - 2 < 0 \ x = 1 \ x = - 2 \ ( - infty . - 2) (1. + infty )$