Question

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Log5(2x+3)=log5(x+1)

Answer 1

$log_5(2x+3)=log_5(x+1); ; ,\\ODZ:; left { {{2x+3>0} atop {x+1>0}} right. ; left { {{x>-1,5} atop {x>-1}} right. ; ; Rightarrow ; ; underline {x>-1}\\2x+3=x+1\\2x-x=1-3\\x=-2<-1; ; Rightarrow ; ; underline {xin varnothing }\\Otvet:; ; reshenij; net; .$