Question

Решите неравенство: (-19)/(〖(х+5)〗^2-6)≥0

Answer 1

$sf dfrac{-19}{(x+5)^2-6} geq 0 \(x+5)^2-6<0 \ (x+5-sqrt{6})(x+5+ sqrt{6})<0 \ x in (-5- sqrt{6}; -5+ sqrt{6})$

Ответ: x∈(-5-√6; -5+√6)