Question

log1/3(2x+1)=3
Помогите подалуйстаааа

Answer 1

ОДЗ: 2х + 1 > 0 <=> х > - 0,5


$log_{ frac{1}{3} }(2x + 1) = 3 \ \ log_{ frac{1}{3} }(2x + 1) = log_{ frac{1}{3} }( frac{1}{27} ) \ \ 2x + 1 = frac{1}{27} \ 2x = frac{1}{27} - 1 \ 2x = - frac{ 26}{27} \ x = - frac{13}{27}$


ОТВЕТ: - 13/27