Question

X2+4x+1=0 решите пж ок да

Answer 1

${x}^{2} + 4x + 1 = 0$
$D = {4}^{2} - 4 = 12 \ x(1) = frac{- 4 + sqrt{12}}{2} = - 2 + sqrt{3} \ x(2) = - 2 - sqrt{3}$