Question

Постройте график функции:

Answer 1

$sf y=dfrac{4x-4}{x-x^2}=dfrac{4(x-1)}{x(1-x)}=-dfrac{4(x-1)}{x(x-1)}=-dfrac{4}{x}$

Область определения:  $sf left [ begin{array}{I}sf x neq 0 \ sf x-1 neq 0 end{array} Rightarrow x in (-infty; 0) cup (0; 1) cup (1; + infty)$

Нули функции: ∅