Question

Срочно!!!
Номер 3 и 4

Answer 1

это №3
а)
$frac{1}{3} c = ( frac{1}{3} times ( - frac{3}{1} ).. frac{1}{3} times frac{6}{1} ) = ( - 1..3) [tex]a = frac{1}{3} c - b = ( - 1 - 2..3 - ( - 2)) = ( - 3..1) \ a = ( - 3..1)$

б)
$a = sqrt{ {( - 3)}^{2} + {1}^{2} } = sqrt{9 + 1} = sqrt{10}$