Question

Номер три ответь буду рад много балов

Answer 1

$1)frac{c^{3} }{c^{2}-8c+16 }-frac{c^{2} }{c-4}=frac{c^{3} }{(c-4)^{2} }-frac{c^{2} }{c-4} =frac{c^{3}-c^{3}+4c^{2}}{(c-4)^{2} }=frac{4c^{2} }{(c-4)^{2}}\\2)frac{c^{2} }{c^{2}-16 }-frac{c}{c-4}=frac{c^{2} }{(c-4)(c+4)}-frac{c}{c+4}=frac{c^{2}-c^{2} -4c }{(c-4)(c+4)} =frac{-4c}{(c-4)(c+4)}\\3)frac{4c^{2} }{(c-4)^{2} } :frac{-4c}{(c-4)(c+4)}=frac{4c^{2} }{(c-4)^{2} }*frac{(c-4)(c+4)}{-4c}=-frac{c(c+4)}{c-4} =frac{c^{2} +4c}{4-c}$

Тождество доказано

Answer 2

1. c³/(c²-8c+18)=c³/(c-4)².

2. c³/(c-4)²-c²/(c-4)=(c³-c²*(c-4))/(c-4)=(c³-c³+4c²)/(c-4)²=4c²/(c-4)².

3. c²/(c²-16)-c/(c-4)=c²/((c-4)(c+4))-c/(c-4)=(c²-c*(c+4))/(c²-16)=

=(c²-c²-4)/(c²-16)=-4c/(c²-16).

4. (4c²/(c-4)²):(-4c/(c²-16))=4c²*(c-4)*(c+4)/(-4c*(c-4)²)=-c*(c+4)/(c-4)=

=c*(c+4)/(4-c)=(c²+4c)/(4-c).