Question

2cos 6x - корень из 2 =0
помогите срочноооо

Answer 1

cos6x=sqr(2)/2
6x=arccos(sqr(2)/2)=+-(pi/4) +2*pi*n
x=+-(pi/24)+pi*n/3

Answer 2

$2Cos6x-sqrt{2}=0\\2Cos6x=sqrt{2} \\Cos6x=frac{sqrt{2} }{2}\\6x=+-arcCosfrac{sqrt{2} }{2}+2pi n,nez \\6x=+-frac{pi }{4}+2pi n,nez\\x=+-frac{pi }{24}+frac{pi n }{3},nez$