Question

Укажите число корней в уравнении: х^2-8х+17=1. Назовите их

Answer 1

$x {}^{2} - 8x + 16 = 0 \ d = 8 {}^{2} - 4 times ( - 16) = 128 \ x = - ( - 8) + - sqrt{128} \ x1 = 8 + 8 sqrt{2} = 4 + 4 sqrt{2} \ x2 = 8 - 8 sqrt{2} = 4 - 4 sqrt{2}$

Answer 2

${x}^{2} - 8x + 17 = 1 \ {x}^{2} - 8x + 16 = 0 \ {(x - 4)}^{2} = 0 \ x - 4 = 0 \ x = 4$