Question

9 sqrt{x - 1}=x^2 sqrt{x - 1}

Answer 1

$9 sqrt{x - 1}=x^2 sqrt{x - 1}$

D:

$x ge 1$

$x^2 sqrt{x - 1}-9 sqrt{x - 1}=0$

$sqrt{x - 1}(x^2-9)=0$

$sqrt{x - 1}(x-3)(x+3)=0$

$sqrt{x - 1}=0 x-3=0 x+3=0$

$x=1 x=3 x=-3<1$

Ответ

x=1,x=3