Question

A{1;-2}, b{-3;3}, c{4;0}
Найти |a|, |b|, |c|
Y=a+b+2c

Answer 1

|a| = √(1² + (-2)²) = √5

|b| = √((-3)² + 3²) = √18 = 3√2

|c| = √(4² + 0²) = √16 = 4

Y = (1 + (-3) + 2*4; -2 + 3 + 2*0) = (6; 1)

Answer 2

$vec{a}=(1;-2); ,; ; vec{b}=(-3;3); ,; ; vec{b}=(4;0)\\|vec{a}|=sqrt{1^2+2^2}=sqrt5\\|vec{b}|=sqrt{3^2+3^2}=sqrt{18}=3sqrt2\\|vec{c}|=sqrt{4^2+0^2}=4\\vec{y}=vec{a}+vec{b}+2vec{c}=(1-3+8, ;, -2+3+0)=(6, ;, 1)$