Question

sin П/6+ корень 2 cos п/4-корень 3 ctgП/3

Answer 1

$Sinfrac{pi }{6}+sqrt{2}Cosfrac{pi }{4}-sqrt{3}Ctgfrac{pi }{3}=frac{1}{2}+sqrt{2}*frac{sqrt{2} }{2}-sqrt{3}*frac{1}{sqrt{3} } =frac{1}{2}+1-1=0,5$