Question

Найдите корни уравнения

Answer 1

$frac{2x+3}{2}-frac{x^{2}+6x}{6}=1 \frac{6x+9}{6}-frac{x^{2}+6x}{6}=1$

$frac{6x+9-x^{2}-6x }{6}=1\ 6x+9-x^{2}-6x=6\-x^{2}=-3\x^{2}=3\x_{1}=sqrt{3}\x_{2}=-sqrt{3}$