Question

Найдите корень уравнения 2^log3(9x+9)=6

Answer 1

$2^{log_3(9x + 9)} = 6\3^{log_3(2) cdot log_3(9x + 9)} = 6\(9x + 9)^{log_3(2)} = 6\9x + 9 = 6^{log_2(3)}\x = frac{6^{log_2(3)}}{9} - 1$